An electric motor pump is 60% efficient and is rated 2.5 H.P. Calculate the maximum load it can lift through a height of 10m in 8 sec. (1 H.P. = 750 W).


Video Solution


⚙️ Electric Motor Pump: Maximum Load Calculation

Given:
Efficiency, η = 60% = 0.6
Power rating, P = 2.5 H.P. = 2.5 × 750 = 1875 W
Height, h = 10 m
Time, t = 8 s
Acceleration due to gravity, g = 9.8 m/s² (assumed)

Step 1: Calculate Output Power

Output power = Efficiency × Input power = 0.6 × 1875 = 1125 W

Step 2: Calculate Work Done to Lift Load

Work done (W) = Power output × time = 1125 × 8 = 9000 J

Step 3: Calculate Maximum Load (mass)

Work done to lift load = m × g × h
So, m = Work done / (g × h) = 9000 / (9.8 × 10) = 9000 / 98 ≈ 91.84 kg

Final Answer:

The motor pump can lift a maximum load of approximately 91.8 kg through 10 meters in 8 seconds.

Advertisements

Trending

HTML Snippets Powered By : XYZScripts.com

Discover more from Study Doubt

Subscribe now to keep reading and get access to the full archive.

Continue reading