A ray of light passes through an equilateral glass prism, such that the angle of incidence is equal to the angle of emergence. If the angle of emergence is 3/4 times the angle of the prism. The refractive index of the glass prism is(A) 1.71(B) 1.61(C) 1.41(D) 1.21


Video Solution


Refractive Index of an Equilateral Prism

A ray of light passes through an equilateral glass prism such that the angle of incidence equals the angle of emergence. The angle of emergence is 3/4 of the angle of the prism. Find the refractive index of the prism.

Step 1: Given Data

Angle of prism (A) = 60° (Equilateral prism)
Angle of emergence (e) = 3/4 A
e = 3/4 × 60°
e = 45°
Since angle of incidence equals angle of emergence,
i = e = 45°

Step 2: Use Prism Relation

For a prism:

r₁ + r₂ = A

When i = e (minimum deviation condition):

r₁ = r₂ = A/2
r = 60° / 2 = 30°

Step 3: Apply Snell’s Law

μ = sin i / sin r
μ = sin 45° / sin 30°
μ = 0.707 / 0.5
μ = 1.414

Final Answer

Refractive Index ≈ 1.41
Correct Option: (C)

Theory: Minimum Deviation in a Prism

When a ray passes symmetrically through a prism (angle of incidence equals angle of emergence), the prism is said to be in the condition of minimum deviation.

Important Relations

1. Prism relation: r₁ + r₂ = A
2. For minimum deviation: r₁ = r₂ = A/2
3. Snell’s Law: μ = sin i / sin r

For an equilateral prism, A = 60°. Therefore internal refraction angle becomes 30°.

Frequently Asked Questions

Why is the prism in minimum deviation condition?

Because the angle of incidence equals the angle of emergence, the light path inside the prism is symmetrical.

Why is A equal to 60°?

An equilateral prism has all internal angles equal to 60°.

Why is r equal to A/2?

Under minimum deviation, r₁ = r₂, so each equals half the prism angle.

Which formula gives refractive index?

Snell’s law is applied at the first refracting surface: μ = sin i / sin r.

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