A giant refracting telescope at an observatory has an objective lens of focal length 15m. If an eyepiece of focal length 1.0cm is used, what is the angular magnification of the telescope? (b) If this telescope is used to view the moon, what is the diameter of the image of the moon formed by the objective lens? The diameter of the moon is 3.48 × 106 m, and the radius of lunar orbit is 3.8 × 108 m.


Video Solution

Angular Magnification of Giant Refracting Telescope

Angular Magnification of a Giant Refracting Telescope

A giant refracting telescope has an objective lens of focal length 15 m and an eyepiece of focal length 1.0 cm. We calculate:

(a) Angular magnification
(b) Diameter of the image of the Moon formed by the objective

Part (a): Angular Magnification

For a telescope in normal adjustment:

M = fo / fe
fo = 15 m
fe = 1.0 cm = 0.01 m
M = 15 / 0.01 = 1500

Answer (a)

Angular Magnification = 1500

Part (b): Diameter of Image of the Moon

Angular size of Moon:

θ = Diameter of Moon / Distance to Moon
θ = (3.48 × 106) / (3.8 × 108)
θ ≈ 9.16 × 10-3 radians

Image formed at focal plane:

Image diameter = fo × θ
= 15 × 9.16 × 10-3
≈ 0.137 m ≈ 13.7 cm

Answer (b)

Diameter of Moon’s Image ≈ 13.7 cm

Thus, the telescope produces an angular magnification of 1500 times, and the objective forms a real image of the Moon about 14 cm in diameter.

Frequently Asked Questions

What is the formula for angular magnification of a refracting telescope?

For a telescope in normal adjustment, the angular magnification is given by M = fo / fe, where fo is the focal length of the objective and fe is the focal length of the eyepiece.

Why is the angular magnification so large for observatory telescopes?

Observatory telescopes use very large focal length objectives and very small focal length eyepieces. This makes the ratio fo / fe very large, resulting in high angular magnification.

How is the diameter of the Moon’s image calculated?

The objective forms a real image at its focal plane. The image diameter is given by Image size = fo × θ, where θ is the angular size of the Moon.

Why is the image formed by the objective real?

The objective lens focuses parallel rays coming from distant objects (like the Moon) at its focal plane, forming a real, inverted image.

What are the final results of this problem?

The angular magnification of the telescope is 1500, and the diameter of the Moon’s image formed by the objective is approximately 13.7 cm.

Theory: Refracting Telescope

1. Construction and Basic Principle

A refracting telescope consists of two convex lenses:

• Objective lens –

Refracting Telescope – Complete Theory

A refracting telescope is an optical instrument used to observe distant objects such as planets, stars, and the Moon. It works by collecting parallel rays of light using a large objective lens and magnifying the image using an eyepiece.


🔹 1. Construction of a Refracting Telescope

Objective Lens
• Large focal length
• Large aperture
• Forms a real, inverted image
Eyepiece
• Small focal length
• Acts as a magnifier
• Enlarges the image formed by the objective

🔹 2. Working Principle

Light from distant celestial objects arrives at the telescope as nearly parallel rays. The objective lens focuses these rays at its focal plane, forming a real image. The eyepiece then magnifies this image to increase angular size.

Angular Magnification (Normal Adjustment):

M = fo / fe

🔹 3. Image Formation by Objective

The size of the image formed at the focal plane depends on the angular size of the object.

Image Size = fo × θ

Where θ is the angular size in radians.

🔹 4. Why Observatory Telescopes Have Huge Magnification

Large telescopes use extremely long focal length objectives and short focal length eyepieces. Since magnification depends on the ratio fo / fe, a large ratio produces very high angular magnification.

Greater fo → Larger real image
Smaller fe → Greater magnification

This is why giant refracting telescopes can produce detailed images of distant celestial bodies.

Large focal length and large aperture
• Eyepiece – Small focal length

The objective lens collects light from distant objects (like the Moon) and forms a real, inverted image at its focal plane. The eyepiece then acts as a magnifier and enlarges this image for the observer.

2. Normal Adjustment of Telescope

In normal adjustment, the final image is formed at infinity. This allows comfortable viewing because the eye remains relaxed.

Angular Magnification (Normal Adjustment):
M = fo / fe

Where:

fo = Focal length of objective
fe = Focal length of eyepiece

3. Image Formation by the Objective

For distant astronomical objects, light rays reaching the telescope are nearly parallel. The objective forms the image at its focal plane.

Image Size = fo × θ

Where:

θ = Angular size of the object (in radians)

4. Why Large Telescopes Have High Magnification

Observatory telescopes use very large focal length objectives and small focal length eyepieces. Since magnification depends on the ratio fo / fe, increasing this ratio greatly increases angular magnification.

Greater fo → Larger image at focal plane
Smaller fe → Greater magnification

Thus, giant refracting telescopes produce highly magnified and detailed images of distant celestial bodies.

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